Marco/IDB-Zusammenfassung
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untere Schranke für den B-Baum angepasst

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Vergleiche hierzu Lösung zu Blatt 6, Seite 3.
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Alexander Schroth 2019-02-13 18:04:31 +01:00
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@ -134,7 +134,7 @@
\end{itemize} \end{itemize}
\item Höhe: \begin{itemize} \item Höhe: \begin{itemize}
\item obere Schranke: $h(n) = \log_{k+1}\left(\frac{n+1}{2}\right) + 1$ \item obere Schranke: $h(n) = \log_{k+1}\left(\frac{n+1}{2}\right) + 1$
\item untere Schranke: $h(n) = \log_{k+1}\left(k + 1 \right)$ \item untere Schranke: $h(n) = \log_{2k+1}\left(n + 1 \right)$
\end{itemize} \end{itemize}
\end{itemize} \end{itemize}
\item \begriff{B*-Baum} / \begriff{B+-Baum}: \begin{itemize} \item \begriff{B*-Baum} / \begriff{B+-Baum}: \begin{itemize}