Fold in Haskell aus Übung
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fold.tex
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fold.tex
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% !TeX encoding = UTF-8
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\documentclass[a4paper]{scrartcl}
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\usepackage[ngerman]{babel}
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\usepackage[utf8]{inputenc}
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\usepackage{lmodern}
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\usepackage[T1]{fontenc}
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\usepackage{microtype}
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\usepackage{amsmath}
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\usepackage{amssymb}
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\usepackage{amsfonts}
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\usepackage{enumitem}
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\usepackage{listings}
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\usepackage{xcolor}
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\usepackage{tikz}
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\usepackage{ziffer}
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\usepackage{lscape}
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\lstset{
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breaklines=true,
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postbreak=\mbox{\textcolor{red}{$\hookrightarrow$}\space}
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}
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\usepackage{mathrsfs}
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\usepackage{multicol}
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\usepackage{datetime}
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\usepackage[left=1.5cm, right=1.5cm, top=1.5cm, bottom=2.5cm]{geometry}
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\newcommand{\RM}[1]{\MakeUppercase{\romannumeral #1}}
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\usepackage[autostyle=true,german=quotes]{csquotes}
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\KOMAoptions{parskip=half, fontsize=12pt}
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\setkomafont{disposition}{\normalcolor\bfseries}
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\definecolor{fau}{RGB}{26, 71, 115} % FAU Blau
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\definecolor{natfak}{RGB}{56, 132, 105} % NatFak Grün
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\definecolor{wiso}{RGB}{131, 34, 44} % WISO Rot
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\definecolor{philfak}{RGB}{156, 109, 39} % PhilFak Gelb
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% \lstset{frame=tb,
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% aboveskip=3mm,
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% belowskip=3mm,
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% showstringspaces=false,
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% columns=flexible,
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% basicstyle={\small \ttfamily},
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% flexiblecolumns=false,
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% keywordstyle=\color{fau_blau}\bfseries,
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% commentstyle=\color{fau_tf_grau},
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% stringstyle=\color{dkgreen},
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% breaklines=true,
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% breakatwhitespace=true,
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% tabsize=4
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% }
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\usepackage[newfloat,cache=false]{minted}
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% Line numbers not flowing out of the margin
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\setminted{numbersep=5pt, xleftmargin=5pt}
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%\usemintedstyle{bw} %black and white style
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%\usemintedstyle{vs} %visual studio
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%\usemintedstyle{friendlygrayscale} % custom style - submitted as pull request https://bitbucket.org/birkenfeld/pygments-main/pull-requests/748/add-style-friendly-grayscale/diff
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\usemintedstyle{friendly}
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%\usemintedstyle{eclipse} %http://www.jevon.org/wiki/Eclipse_Pygments_Style
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%\usemintedstyle{autumn}
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%\usemintedstyle{rrt}
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%\usemintedstyle{borland}
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\input glyphtounicode
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\pdfgentounicode=1
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\title{ThProg --- Fold in Haskell}
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\begin{document}
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\maketitle
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\inputminted[linenos=true,tabsize=2, obeytabs,breaklines]{haskell}{folds.hs}
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\end{document}
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109
folds.hs
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folds.hs
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import qualified Prelude
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-- Paare
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fst :: (a, b) -> a
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fst (x, _) = x
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snd :: (a, b) -> b
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snd (_, y) = y
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-- Funktionskomposition
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(.) :: (b -> c) -> (a -> b) -> a -> c
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(f . g) x = f (g x)
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-- Identitätsfunktion
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id :: a -> a
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id x = x
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data Bool = True | False deriving (Prelude.Show, Prelude.Eq)
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foldb :: a -> a -> Bool -> a
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foldb a b True = a
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foldb a b False = b
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data Nat = Zero | Succ Nat deriving (Prelude.Eq)
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foldn :: a -> (a -> a) -> Nat -> a
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foldn c g Zero = c
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foldn c g (Succ n) = g (foldn c g n)
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zero = Zero
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one = Succ Zero
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two = Succ one
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three = Succ two
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four = Succ three
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add :: Nat -> Nat -> Nat
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add m = foldn m Succ
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mult :: Nat -> Nat -> Nat
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mult m = foldn Zero (add m)
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exp :: Nat -> Nat -> Nat
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exp m = foldn (Succ Zero) (mult m)
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data List a = Nil | Cons a (List a) deriving (Prelude.Show, Prelude.Eq)
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-- fold für Listen
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foldL :: b -> (a -> b -> b) -> List a -> b
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foldL c g Nil = c
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foldL c g (Cons x xs) = g x (foldL c g xs)
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-- scan für Listen
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scanL :: b -> (a -> b -> b) -> List a -> List b
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scanL c g Nil = Cons c Nil
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scanL c g (Cons x xs) = Cons (g x y) ys
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where ys@(Cons y _) = scanL c g xs
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-- alternativ ohne @-Syntax:
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scanL' :: b -> (a -> b -> b) -> List a -> List b
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scanL' c g xs = snd (scanLHelper c g xs)
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where
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scanLHelper c g Nil = (c, Cons c Nil)
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scanLHelper c g (Cons x xs) = (z, Cons z (snd ys))
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where
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ys = scanLHelper c g xs
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z = g x (fst ys)
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length :: List a -> Nat
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length l = foldL Zero (\x -> Succ) l
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snoc :: a -> List a -> List a
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snoc a l = foldL (Cons a Nil) Cons l
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reverse :: List a -> List a
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reverse l = foldL Nil snoc l
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-- cat ohne foldr
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concat :: List a -> List a -> List a
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concat Nil = id
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concat (Cons x xs) = \ys -> Cons x (concat xs ys)
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-- cat mit foldr
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cat' :: List a -> List a -> List a
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cat' xs ys = foldL ys Cons xs
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data Tree a = Leaf a | Node (Tree a) (Tree a) deriving (Prelude.Show, Prelude.Eq)
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-- fold für Bäume
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foldt :: (a -> b) -> (b -> b -> b) -> Tree a -> b
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foldt c g (Leaf x) = c x
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foldt c g (Node x y) = g (foldt c g x) (foldt c g y)
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-- front ohne foldt
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front :: Tree a -> List a
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front (Leaf x) = Cons x Nil
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front (Node x y) = concat (front x) (front y)
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-- front mit foldt
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front' :: Tree a -> List a
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front' = foldt (\x -> Cons x Nil) concat
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-- Fakultätsfunktion aus der Vorlesung
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fact :: Nat -> Nat
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fact = f . foldn c h
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where
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f = snd
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c = (Zero, one)
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h = (\(x,y) -> (Succ x, mult (Succ x) y))
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